
By Professor Dipl.-Ing. Hermann Linse (auth.)
?ber den Autor/Hrsg
Prof. Dipl.-Ing. Hermann Linse, Esslingen (verst.) Prof. Dr.-Ing. Rolf Fischer, FH Esslingen
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Example text
50b) i = C - U e- t / T T oder i = _!!. 52c) Der Entladestrom hat also denselben Funktionsverlauf wie der Ladestrom, aber die entgegengesetzte Richtung. Die Kondensatorspannung klingt nach einer Exponentialfunktion mit der Zeitkonstanten T auf Null ab (s. 43b). ; = i C U 2 wird wahrend des Entladevorgangs im Widerstand R restlos in Warme umgesetzt.
26). x? l = UBI; R = UB/I. x = 0,72 W/lO W = 7,2%. 26 Solarzelle. MeBsehaltung (a) zur Aufnahme der Kennlinien, Kennlinienbild (b) b) Wie groB muB R gewiihlt werden, damit die Batterie im Arbeitspunkt (A) maximaler Leistung betrieben wird (Anpassung)? Man zeiehne die Widerstandskennlinie UR = f (I) in das Sehaubild ein und erliiutere, warum dieser und aueh jeder andere Arbeitspunkt stabil ist. R = 50,8 V/l,? A = 29,9 Q. Bei einer Abweiehung des Stroms I links vom Arbeitspunkt A ist UB > UR' d. h.
2120 Umdr. Dies entspricht einer bezogenen elektrischen Energie von (2120/800) kWh = 2,65 kWh und damit einer Leistung PI = 2,65 kW. Der Motorstrom ist 1= P,/UN = 2650 W/220 V = 12 A. f) Wie groB sind die taglichen Kosten fUr die gelieferte elektrische Energie bei einem Tarifpreis von 15 Pf/kWh, wenn der Motor 8 h bei Nennlast und 16 h mit der Leistung bei e) in Betrieb ist? Die bezogene elektrische Energie ist W = 4,51 kW· 8 h + 2,65 kW . 16 h = (36,1 + 42,4) kWh = 78,5 kWh und die Kosten K = 78,5 kWh· 0,15 DM/kWh = 11,77 DM.